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Custom sprinkler flow rate

回覆來自 Wency Pan

Wency Pan
更新時間 2023-05-31 08:48:32 UTC

Dear customer,

The default flow rate specification of Netro is measured in mm/h, while your sprinklers are specified in l/min. These are two different units of measurement and cannot be directly compared. To convert from l/min to mm/h, you would need to know the area covered by each sprinkler and the number of the heads.

The calculation of the flow rate requires the acreage of the irrigation area, here's the calculation formula to help better understand :

Count the number of sprinkler head n, if all heads (typicall yes) have the same Liters per minute, calculate V = L/min * 60 mins * n, which is the total volume of water provided by all heads in an hour.
Measure or estimate your zone area A in the unit of m^2. 3. The flow rate PR= 1000V/A, which is the average depth of water your zone gets in an hour.

We understand that it would be useful to have the flow rate specified when selecting sprinkler types for zones. We appreciate your feedback on this matter and will take it into consideration for future updates.

Thanks,

Wency

Netro Support

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<p>
	<span class="text-only">Dear customer,</span>
</p>
<p>
	<span class="text-only"><br />
</span>
</p>
<div class="rich-text-paragraph">
	<span class="text-only">The default flow rate specification of Netro is measured in mm/h, while your sprinklers are specified in l/min. These are two different units of measurement and cannot be directly compared. To convert from l/min to mm/h, you would need to know the area covered by each sprinkler and the number of the heads.</span>
</div>
<div class="rich-text-paragraph">
	<span class="text-only">The calculation of the flow rate requires the acreage of the irrigation area, here's the calculation formula to help better understand : </span>
</div>
<ol class="richTextDocs-orderList richTextDocs-orderList-marker1 richTextDocs-orderList-number">
	<li class="richTextDocs-listItem">
		<div class="richTextDocs-listItem__text">
			<span class="text-only">Count the number of sprinkler head n, if all heads (typicall yes) have the same Liters per minute, calculate V = L/min * 60 mins * n, which is the total volume of water provided by all heads in an hour. </span>
		</div>
	</li>
	<li class="richTextDocs-listItem">
		<div class="richTextDocs-listItem__text">
			<span class="text-only"><span class="text-only text-with-abbreviation text-with-abbreviation-bottomline windows-bottomline">Measure</span><span class="text-only"> or estimate your zone area A in the unit of </span><span class="text-only text-with-abbreviation text-with-abbreviation-bottomline windows-bottomline">m</span><span class="text-only">^2. 3. The flow rate </span><span class="text-only text-with-abbreviation text-with-abbreviation-bottomline windows-bottomline">PR</span><span class="text-only">= 1000V/A, which is the average depth of water your zone gets in an hour. </span></span>
		</div>
	</li>
</ol>
<p>
	<span class="text-only">We understand that it would be useful to have the flow rate specified when selecting sprinkler types for zones. We appreciate your feedback on this matter and will take it into consideration for future updates.</span>
</p>
<p>
	<span class="text-only"><br />
</span>
</p>
<p>
	<span class="text-only">Thanks, </span>
</p>
<p>
	<span class="text-only">Wency</span>
</p>
<div class="rich-text-paragraph">
	<span class="text-only">Netro Support</span>
</div>

取消

Jure
2023-06-01 14:58:27 UTC

Thanks, is the following calculation correct: I have 1 A = 35m2
V = 3 sprinklers (each 6 l/min).

So average mm/h for this zone would be:
3 x 6 l/min x 60 min = 1080 l/h
1080 / 35 = 30,85 mm/h per m2

is this correct?

Wency Pan
2023-06-02 02:15:19 UTC

Dear Jure,

I apologize for the mistake in the formula that I provided to you earlier. I have corrected the calculation and the correct conversion is 1080L = 1.08m^3. Therefore, PR = 1.08/35m = 1080/35mm. With this correction, the V/A calculation should now be accurate.

Thanks,
Wency